Question

If sin A = 1/3 then find the value of cos A . cosec A + tan A . sec A

Answer 1

sin A = \(\frac { 1 }{ 3 }\)

Now we will construct a triangle ABC in which ∠B 

= 90° and BC : AC = 1 : 3

Let BC = k and AC = 3k 

where k > 0 which is a constant quantity.