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+2 votes
in Chemistry by (2.8k points)
Note: Pls give the solution.....

1 Answer

+1 vote
by (128k points)
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Best answer

We have Fe3+=x and Fe2+=.93-x

then using charge balance..


( 1 for oxygen)


% of Fe3+=(.14/.93)*100=15%

% of Fe2+=(.79/.93)*100=85%

by (2.8k points)
How did this method do it?, pls explain what is it
by (2.8k points)
Doesn't the question have the rario of Fe per O

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