+2 votes
4.7k views
in Chemistry by (2.8k points)
Note: Pls give the solution.....

1 Answer

+1 vote
by (128k points)
selected by
 
Best answer

We have Fe3+=x and Fe2+=.93-x

then using charge balance..

3*x+2*(0.93-x)=2*1

( 1 for oxygen)

x=.14

% of Fe3+=(.14/.93)*100=15%

% of Fe2+=(.79/.93)*100=85%

by (2.8k points)
How did this method do it?, pls explain what is it
by (2.8k points)
Doesn't the question have the rario of Fe per O

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...