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in Trigonometric Ratios of Acute Angles by (31.2k points)
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Prove that tan2A + tan4A = sec4A – sin2A.

1 Answer

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Best answer

L.H.S. = tan2A + tan4

= tan2A (1 + tan2A) 

= (sec2A – 1) sec2

= sec4A – sec2

= R.H.S.

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