Question

In a Mathematics test given by 15 students, the following marks (out of 100) are recorded: 41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60 Find the mean, median and mode of these data.

Answer 1

(i) Mean:

i.e, ((n + 1)/2)^th = ((15 + 1)/2)^th 

= 8^th term

Median = T₈ = 52

Hence, mean of the given data is 54.8. 

(ii) Median: Arranging the given data in the ascending order, we have 39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98 

Here, n = 15 which is odd, 

so their will be only one median class

(iii) Here, the mark 52 occurred most frequently i.e. 3 times. 

Hence, Mode = 52.