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Find the median of the following distribution 12, 1, 6, 4, 10, 8, 1, 4.

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Arranging the distribution in ascending order, we get
1, 1, 4, 4, 6, 8, 10, 12

Here, n = 8 (even). 

So, their will be two median terms

i.e. (\(\frac { n }{ 2 }\))th, (\(\frac { 1 }{ 2 }\) + 1)th

Here, \(\frac { n }{ 2 }\) = \(\frac { 8 }{ 2 }\) = 4

Median = \(\frac { 4^{th} \;term + 5^{th} \;term }{ 2 }\) 

\(\frac { 4 + 6 }{ 2 }\) = 5

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