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In Fig., PQ = PS. The value of x is 

(a) 35° (b) 45° (c) 55° (d) 70°

1 Answer

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Best answer

(b) 45o

From the given figure,

In triangle PQS, ∠PSQ + ∠QPS = 110o … [from exterior angle property of a triangle]

We know that, sum of all angle of the triangle is equal to 180o.

So, ∠PSQ + ∠QPS + ∠PQS = 180o

110o + ∠PQS = 180o – 110o

∠PQS = 70o

Now, consider the triangle PRS,

∠PSQ = x + 25o … [from the exterior angle property of a triangle]

x = 70o – 25o

x = 45o

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