(d) (i) and (ii)
From the question it is given that,
One angle of isosceles triangle is 70o.
We know that, in an isosceles triangle 2 angles are equal corresponding with 2 equal sides,
If 70o is 3rd angle of triangle,
70o + x + x = 180o
2x + 70o = 180o
2x = 180o – 70o
x = (110o/2)
x = 55o
So, both angles are 55o
Consider the 70o as base angle of isosceles triangle
Then, 70o + 70o + x = 180o
x = 180o – 140o
x = 40o
So, one angle is 40o and another is 70o