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In the given figure, ΔPQR is right angled at P. U and T are the points on line QRF. If QP || ST and US || RP, find ∠S.

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If QP || ST and QT is a transversal, then ∠PQR = ∠STU                      [alternate interior angles]

and if DS || RP and QT is a transversal, then ∠PRQ = ∠SUT              [alternate interior angles]

Hence, ∠S must be equal to ∠Pi.e. 90°.

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