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0 votes
2.4k views
in Chemical Kinetics by (15 points)
for gaseous reactions, rate=A B.if volume of container is reduced to 1/4 of initial then the rate of rection will be

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2 Answers

+1 vote
by (47.3k points)

AS rate =K[A][B] where [A] = conc of A
[B] = conc. of B

conc. = no of moles / volume

therefore we decrease the volume of vessel to1/4 th initial volume .the conc. of A  and  B  both will increase by 4 times { conc. is inversely proportional to volume } .
so final conc. of A will become = 4[A]
final conc. of B will become = 4[B]

final rate of rxn = k{4[A]*4[B] }

= 16k[A][B]

= 16 {initial rate of reaction}

0 votes
by (15 points)

When the volume of the reaction vessel reduces to 1/4th of its initial volume, the molar concentration of each reactant increases four times. Hence the rate of reaction will be 16 times of initial.

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