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How many different boat parties of 8, consisting of 5 boys and 3 girls, can be made from 25 boys and 10 girls?

1 Answer

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Best answer

Given as

The total boys are = 25

The total girls are = 10

The boat party of 8 to be made from 25 boys and 10 girls, by selecting 5 boys and 3 girls.

Therefore,

On using the formula,

nCr = n!/r!(n – r)!

25C5 × 10C3 = 25!/5!(25 – 5)! × 10!/3!(10-3)!

= 25! / (5! 20!) × 10!/(3! 7!)

= [25 × 24 × 23 × 22 × 21 × 20!]/(5! 20!) × [10 × 9 × 8 × 7!]/(7! 3!)

= [25 × 24 × 23 × 22 × 21]/5! × [10 × 9 × 8]/(3!)

= [25 × 24 × 23 × 22 × 21]/(5 × 4 × 3 × 2 × 1) × [10 × 9 × 8]/(3 × 2 × 1)

= 5 × 2 × 23 × 11 × 21 × 5 × 3 × 8

= 53130 × 120

= 6375600

Hence, the total number of different boat parties is 6375600 ways.

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