Question

Find the 7th term from the end in the expansion of (2x² – 3/2x) ⁸.

Answer 1

Given as

(2x² – 3/2x) ⁸

Let T_r+1 be the 4^th term from the end of the given expression.
Now, T_r+1 is (9 − 7 + 1)^th term, i.e., 3rd term, from the beginning.
T₃ = T₂₊₁

∴ The 7^th term from the end is 4032 x¹⁰.