Given as
(x2 + 1/x)12
If x-1 occurs at the (r + 1)th term in the given expression.
Now, we have:
Tr+1 = nCr xn-r ar
Now, for this term to contain x-1, we must have
24 – 3r = -1
3r = 24 + 1
3r = 25
r = 25/3
It is not possible, since r is not an integer.
Thus, there is no term with x-1 in the given expansion.