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Find the term independent of x in the expansion of the following expressions:

(i) (3/2 x2 – 1/3x)9

(ii) (2x + 1/3x2)9

(iii) (2x2 – 3/x3)25

(iv) (3x – 2/x2)15

(v) ((√x/3) + √3/2x2)10

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(i) (3/2 x2 – 1/3x)9

Given as

(3/2 x2 – 1/3x)9

If (r + 1)th term in the given expression is independent of x.

Now, we have:

Tr+1 = nCr xn-r ar

For this term to be independent of x, we must have

18 – 3r = 0

3r = 18

r = 18/3

= 6

Therefore, the required term is 7th term.

We have,

T7 = T6+1

9C6 × (39-12)/(29-6)

= (9 × 8 × 7)/(3 × 2) × 3-3 × 2-3

= 7/18

Thus, the term independent of x is 7/18.

(ii) (2x + 1/3x2)9

Given as

(2x + 1/3x2)9

If (r + 1)th term in the given expression is independent of x.
Now, we have:

Tr+1 = nCr xn-r ar

For this term to be independent of x, we must have

9 – 3r = 0

3r = 9

r = 9/3

= 3

Therefore, the required term is 4th term.

We have,

T4 = T3+1

9C3 × (26)/(33)

9C3 × 64/27

Thus, the term independent of x is 9C3 × 64/27.

(iii) (2x2 – 3/x3)25

Given as

(2x2 – 3/x3)25

If (r + 1)th term in the given expression is independent of x.

Now, we have:

Tr+1 = nCr xn-r ar

25Cr (2x2)25-r (-3/x3)r

= (-1)r 25C× 225-r × 3r x50-2r-3r

For this term to be independent of x, we must have

50 – 5r = 0

5r = 50

r = 50/5

= 10

Therefore, the required term is 11th term.

We have,

T11 = T10+1

= (-1)10 25C10 × 225-10 × 310

25C10 (215 × 310)

Thus, the term independent of x is 25C10 (215 × 310).

(iv) (3x – 2/x2)15

Given as

(3x – 2/x2)15

If (r + 1)th term in the given expression is independent of x.

Now, we have:

Tr+1 = nCr xn-r ar

15Cr (3x)15-r (-2/x2)r

= (-1)r 15Cr × 315-r × 2r x15-r-2r

For this term to be independent of x, we must have

15 – 3r = 0

3r = 15

r = 15/3

= 5

Therefore, the required term is 6th term.

We have,

T6 = T5+1

= (-1)5 15C5 × 315-5 × 25

= -3003 × 310 × 25

Thus, the term independent of x is -3003 × 310 × 25.

(v) ((√x/3) + √3/2x2)10

Given as

((√x/3) + √3/2x2)10

If (r + 1)th term in the given expression is independent of x.

Now, we have:

Tr+1 = nCr xn-r ar

For this term to be independent of x, we must have

(10-r)/2 – 2r = 0

10 – 5r = 0

5r = 10

r = 10/5

= 2

Therefore, the required term is 3rd term.

We have,

T3 = T2+1

Thus, the term independent of x is 5/4.

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