(i) (3/2 x2 – 1/3x)9
Given as
(3/2 x2 – 1/3x)9
If (r + 1)th term in the given expression is independent of x.
Now, we have:
Tr+1 = nCr xn-r ar
For this term to be independent of x, we must have
18 – 3r = 0
3r = 18
r = 18/3
= 6
Therefore, the required term is 7th term.
We have,
T7 = T6+1
= 9C6 × (39-12)/(29-6)
= (9 × 8 × 7)/(3 × 2) × 3-3 × 2-3
= 7/18
Thus, the term independent of x is 7/18.
(ii) (2x + 1/3x2)9
Given as
(2x + 1/3x2)9
If (r + 1)th term in the given expression is independent of x.
Now, we have:
Tr+1 = nCr xn-r ar
For this term to be independent of x, we must have
9 – 3r = 0
3r = 9
r = 9/3
= 3
Therefore, the required term is 4th term.
We have,
T4 = T3+1
= 9C3 × (26)/(33)
= 9C3 × 64/27
Thus, the term independent of x is 9C3 × 64/27.
(iii) (2x2 – 3/x3)25
Given as
(2x2 – 3/x3)25
If (r + 1)th term in the given expression is independent of x.
Now, we have:
Tr+1 = nCr xn-r ar
= 25Cr (2x2)25-r (-3/x3)r
= (-1)r 25Cr × 225-r × 3r x50-2r-3r
For this term to be independent of x, we must have
50 – 5r = 0
5r = 50
r = 50/5
= 10
Therefore, the required term is 11th term.
We have,
T11 = T10+1
= (-1)10 25C10 × 225-10 × 310
= 25C10 (215 × 310)
Thus, the term independent of x is 25C10 (215 × 310).
(iv) (3x – 2/x2)15
Given as
(3x – 2/x2)15
If (r + 1)th term in the given expression is independent of x.
Now, we have:
Tr+1 = nCr xn-r ar
= 15Cr (3x)15-r (-2/x2)r
= (-1)r 15Cr × 315-r × 2r x15-r-2r
For this term to be independent of x, we must have
15 – 3r = 0
3r = 15
r = 15/3
= 5
Therefore, the required term is 6th term.
We have,
T6 = T5+1
= (-1)5 15C5 × 315-5 × 25
= -3003 × 310 × 25
Thus, the term independent of x is -3003 × 310 × 25.
(v) ((√x/3) + √3/2x2)10
Given as
((√x/3) + √3/2x2)10
If (r + 1)th term in the given expression is independent of x.
Now, we have:
Tr+1 = nCr xn-r ar
For this term to be independent of x, we must have
(10-r)/2 – 2r = 0
10 – 5r = 0
5r = 10
r = 10/5
= 2
Therefore, the required term is 3rd term.
We have,
T3 = T2+1
Thus, the term independent of x is 5/4.