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Find three numbers in G.P. whose sum is 65 and whose product is 3375.

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Let the three numbers be a/r, a, ar

So, according to the question

a/r + a + ar = 65 … equation (1)

a/r × a × ar = 3375 … equation (2)
From equation (2) we get,

a3 = 3375

a = 15.

From equation (1) we get,

(a + ar + ar2)/r = 65
a + ar + ar2 = 65r … equation (3)

Substituting a = 15 in equation (3) we get

15 + 15r + 15r2 = 65r

15r2 – 50r + 15 = 0… equation (4)

Dividing equation (4) by 5 we get

3r2 – 10r + 3 = 0

3r2 – 9r – r + 3 = 0

3r(r – 3) – 1(r – 3) = 0

r = 3 or r = 1/3

Now, the equation will be

15/3, 15, 15×3 or

15/(1/3), 15, 15×1/3

So the terms are 5, 15, 45 or 45, 15, 5
∴ The three numbers are 5, 15, 45.

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