(1) NaOH + Cl2→ NaCl + H2O + NaOCl
Here, Let us first balance, Na’ on both sides, then we get an equation.
2NaOH + Cl2→ NaCl + H2O + NaOCl
This is the balanced chemical equation.
(2) NaOH + Cl2→ NaClO3 + NaCl + H2O
Here, on balancing ‘O’ on both sides, by inserting 6 before NaOH, and 3 before, H2O on R.H.S., we get,
6NaOH + Cl2→ NaClO3 + NaCl+ 3H2O
Now, on balancing ‘Cl’ finally, as ‘H’ is balanced on both sides, by inserting 3 before Cl2 in L.H.S. and 5 before NaCl in R.H.S., we get:
6NaOH + 3CL→ NaClO3 + 5NaCl + 3H2O
It has all the atoms of the elements, balanced on both sides. This is a balanced chemical equation.
(3) Cu + HNO3→ Cu(NO3)2 + NO2 + H2O
Let us first balance, ‘H’ and ‘O’ on both sides of the equation by inserting ‘4’ before HNOa in L.H.S. ‘2’ before NO2 and 4 before H2O in R.H.S., we get:
Cu + 4HNO3→Cu(NO3)2 + 2NO2+ 2H2O)
(4) Cu + HNO3→Cu(NO3)2 + NO + H2O
Let us first balance, ‘H’ and ‘O’ on both sides of the equation, by inserting ‘8’ before HNO3 in L.H.S.; 3 before Cu(NOs)2; 2 before NO and 4 before H2O in R.H.S., respectively, we get:”
Cu + 8HNO3→ 3Cu(NO3)2 + 2NO+ 4H2O
Now, to balance ‘Cu’ on both sides, insert ‘3’ before Cu in L.H.S., we get:
3 Cu + 8HNO3→3Cu(NO3)2 + 2NO + 4H2O
(5) Zn + HNO3→ Zn(NO3)2 + H2O + N2O
Let us first balance, ‘H’ and ‘O’ on both sides of the equation by inserting 2 before ‘KMnO4’ in L.H.S., before HNO3 in L.H.S. and 4 before Zn(NO3)2 and 5 before ‘H2O’ in R.H.S. respectively, we get,
4Zn + 10HNO3→ 4Zn(NO3)2 + N2O+ 5H2O
(6) KMnO4 + SO2 + H2O→ K2SO4+ MnSO4 + H2SO4
This equation can be balanced by first balancing ‘O’ and ‘H’ atoms and then ‘K’ and ‘Mn’ atoms, respectively. Similarly as in previous equations, to get the balanced equation as:
2KMnO4 + 5SO2 + 2H2O→ K2SO4 +2MnSO4 + 2H2SO
