Given:
Sum of GP = 728
Where, a = 2, r = 6/2 = 3, n = ?
By using the formula,
Sum of GP for n terms = a(rn – 1 )/(r – 1)
728 = 2 (3n – 1)/(3 - 1)
728 = 2 (3n – 1)/2
728 = 3n – 1
729 = 3n
36 = 3n
6 = n
∴ 6 terms are required to make a sum equal to 728