A man in a lift which is ascending with an upward acceleration 'a' throws a ball vertically upwards with a velocity ‘v’ with respect to himself and catches it after ‘t1’ seconds. Afterwards when the lift is descending with the same acceleration 'a' acting downwards the man again throws the ball vertically upwards with the same velocity with respect to him and catches it after ‘t2’ seconds
the acceleration of the ball with respect to ground is g when it is in air
\text{the velocity v of the ball relative to the lift is }\\\frac{\text{g(t}_1+\text{t}_2)}{\text{t}_1\text{t}_2}
the velocity v of the ball relative to the lift is
t
1
t
2
g(t
1
+t
2
)
\text{the acceleration 'a' of the lift is}\\\frac{\text{g(t}_2-\text{t}_1)}{\text{t}_1+\text{t}_2}
the acceleration ’a’ of the lift is
t
1
+t
2
g(t
2
−t
1
)
\text{the velocity v of the ball relative to the man is }\\\frac{\text{g}\text{t}_1\text{t}_2}{\text{(t}_1+\text{t}_2)}
the velocity v of the ball relative to the man is
(t
1
+t
2
)
gt
1
t
2
