obtain the zeros of the quadratic equation 4x^2+5root2x-3

Question

Obtain the zeros of the quadratic equation 4x^2+5√2x-3

Answer 1

We have polynomial is 4x²+5√2x-3

4x²+5√2x-3=0

a=4

b=5√2

c=-3

D=b²-4ac

D=(5√2)²-4x4x(-3)

D= 50+48

D=98

Apply Quadratic formula 

we got two zeros are -b±√D/2a

- 5✓2 +- ✓ 50+48/2*4
(-5✓2 +- ✓98)/8
therefore zeros of the polynomial are (-5✓2 + ✓98)/8 & (-5✓2 - ✓98)/8