Vertices are of the form (±a, 0), hence major axis is along x-axis.
So, the equation is of the form: x2/a2 + y2/b2 = 1 …..(1)
Given: vertices of ellipse (±6, 0)
Here a = 6
Again,
Foci is of the form (±c, 0)
Given: foci of ellipse at (±4, 0)
⇒ c = 4
Find b:
We know, c2 = a2 – b2
16 = 36 – b2
or b2 = 20
Equation (1)⇒
x2/36 + y2/20 = 1
Which is required equation.