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Find the equation of ellipse whose vertices are at (±6, 0) and foci at (±4, 0).

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Vertices are of the form (±a, 0), hence major axis is along x-axis.

So, the equation is of the form: x2/a2 + y2/b2 = 1 …..(1)

Given: vertices of ellipse (±6, 0)

Here a = 6

Again,

Foci is of the form (±c, 0)

Given: foci of ellipse at (±4, 0)

⇒ c = 4

Find b:

We know, c2 = a2 – b2

16 = 36 – b2

or b2 = 20

Equation (1)⇒

x2/36 + y2/20 = 1

Which is required equation.

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