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Find the equation of ellipse the ends whose major and minor axes are (±4, 0) and (0, ±3) respectively.

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Major axis of the given ellipse lie on x-axis.

Equation of the ellipse will be of the form: x2/a2 + y2/b2 = 1

Whose vertices (±a, 0) and foci (±c, 0)

Here, a = 4

Ends of minor axis: (0, ±3), let A(0, -3) and B(0, 3)

⇒ AB = 6 units = length of minor axis.

⇒ 2b = 6 or b = 3

Therefore, required equation is : x2/16 + y2/9 = 1

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