Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
6.8k views
in Physics by (2.8k points)
A. increase

B. decrease

C. first increase and then decrease

D. remain constant

1 Answer

+2 votes
by (2.1k points)
selected by
 
Best answer

Ans.(B)

The energy comes from the surrounding atmosphere. When the balloon moves up, it displaces the air above it. This air has to be transferred to the space below the balloon. This air is losing its potential energy. For every unit of volume of the balloon gas going up, there is a unit of volume of the surrounding air going down. The gas in the balloon is gaining potential energy, but its density (mass per unit volume) is less than the density of the air that’s losing potential energy, so there is a net decrease of potential energy. This difference of potential energy is converted to the kinetic energy of the rising balloon. Some of it is also dissipated, if the flow of air is not laminar.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...