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There is a box containing 30 bulbs of which 5 are defective. If two bulbs are chosen at random from the box in succession without replacing the first, what is the probability that both the bulbs chosen are defective?

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It is given that a box containing 30 bulbs of which 5 are defective with each trial independent of other trial

Consider success bulb chosen is defective = 5/30

So the probability of success in the first trial

P1 (success) = 5/30

So the probability of success in the second trial without replacement of the first draw

P2 (success) = 4/29

Probability that both the bulbs chosen are defective, with each trial being independent

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