Consider A as the event ‘Arun is selected’ and B as the event ‘Ved is selected’
Here
We know that
P (atleast one of them getting selected) = P (selecting only Arun) + P (selecting only Ved) + P (selecting both)
= P (A and not B) + P (B and not A) + P (A and B)
So we get
We get
= 2/12 + 3/12 + 1/12
= 1/2
Hence, the probability that atleast one of them will get selected is 1/2.