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in Construction of Quadrilaterals by (48.4k points)
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Construct a square in which :

(i) Perimeter is 20 cm.

(ii) Sum of two adjacent sides is 9 cm.

1 Answer

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Best answer

(i) Given that perimeter of a square = 20 cm.

∴ side of a square = Perimeter/4 = 20/4 = 5 cm.

We draw a square whose side = 5 cm.

We know that each angle of a square = 90°

Steps of Construction

(1) First of all draw a line segment AB = 5 cm.

(2) At the point A and B, construct ∠BAX = 90° and ∠ABY = 90° respectively with AB.

(3) From ray AX cuts AD = 5 cm. and from ray by cuts BC = 5 cm.

(4) Join CD.

Thus, we obtained required square ABCD.

(ii) Draw a rough sketch of square of given measurements.

Given that

Sum of two adjacent sides = 9 cm.

So each side of square = 9/2 = 4.5 cm.

Steps of Construction

(1) First of all we draw a line segment AB = 4.5 cm.

(2) At the point A and B we construct ∠BAX = 90° and ∠ABY = 90° with AB respectively.

(3) Similarly from point B, an angle of 90° in made and arc of 4.5 cm is cut. Here, mark this point as C.

(4) Join C and D.

Thus, we obtained a square ABCD.

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