Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.4k views
in Construction of Quadrilaterals by (48.4k points)
closed by

Construct a square PQRS in which diagonals meets at point O and PO = 2.8 cm.

1 Answer

+1 vote
by (49.3k points)
selected by
 
Best answer

First of all we draw a rough sketch of square ABCD of given measurements.

By properties of square we know that diagonals of a square are equal at bisect each other,

∵PO = 2.8 cm.
∴PR = 2 x PO
= 2 x 2.8
= 5.6 cm.

Steps of Construction

(i) We draw a line segment of diagonal PR = 5.6 cm.

(ii) Draw perpendicular bisector XY of PR which intersect at point O.

(iii) Taking O as centre, draw an arc of radius 2.8 cm., both sides of PR which cuts perpendicular bisector XY at Q and S.

(iv) Join PQ, QR, RS and SP.

(v) Thus, we obtained required square PQRS.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...