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in Coordinate Geometry by (48.6k points)
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Prove that the lines (x - 2)/1 = (y - 4)/4 = (z - 6)/7 and (x + 1)/3 = (y + 3)/5 = (z + 5)/7 are coplanar. Also find the equation of the plane containing these lines.

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by (49.9k points)
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Best answer

It is given that

Therefore, given lines are coplanar.

We know that the equation of plane passing through both lines is written as

So we get

– 7x + 14 + 14y – 56 – 7z + 42 = 0

– 7x + 14y – 7z = 0

Multiply the entire equation by –ve sign

x – 2y + z = 0

Hence, the equation of plane is x – 2y + z = 0

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