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Find a vector of magnitude 21 units in the direction of the vector (2i - 3j + 6k).

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Find a vector of magnitude 21 units in the direction of the vector (2i - 3j + 6k).

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Consider λ as an arbitrary constant and the vector can be written as 2λi - 3λj + 6λk

We know that for any vector 

Hence, the required vector is (6i - 9j + 18k)

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