Fewpal
+2 votes
57 views
in JEE by (2.4k points)
Kinetic energy of a particle is increased by 100 %. What is the percentage change in its linear momentum?

1 Answer

+2 votes
by (21.1k points)
selected by
 
Best answer

Let k1 be the initial kinetic energy,k2 be the final kinetic energy.

let p1 be intial momentum & p2 be final momentum.

From question we have,

k2=k1+100%k1

k2=k1+k1=2k1

1\2(mV2)2=2(1\2mV12)

V2=√2V1

on mutiplying by mass m,

mV2=√2mV1

p2=√2p1.         now,

Δp=p2-p1            

=>p1(√2-1)

%age of change in momentum=100(Δp\p1)

= 100(√2 - 1) %

=(1.414-1)100

=41.4%

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...