Here x2 = 6y is a upward parabola having vertex (0, 0) and x2 + y2 = 16 is a circle with (0, 0) as centre and 4 as radius.
So the given curve are
x2 + y2 = 16 …. (1)
x2 = 6y ….. (2)
Now by solving both the equations we get A (- 2 √3, 2) and B (2 √3, 2) as the points
So the required area can be written as
Required area = 2 (area of OBCO)
Here
= 2 (area of ODBCO – area of ODBO)