Here y2 = 8x is a right hand parabola having (0, 0) as the vertex and x2 + y2 = 25 is a circle having (0, 0) as center and 5 units as radius
x2 + y2 = 25 ….. (1)
y2 = 8x ….. (2)
By solving both the equations we get
x2 + 8x – 25 = 0
We get
x = (- 8 ± √(64 + 100)/2
So x = – 4 + √41 is the rejecting negative value
By substituting y = 0 in equation (1) we get x = ± 5
So the circle (1) cuts x-axis at the point C (5, 0) and C’ (-5, 0)
Here the required area = 2 [area of ODCAO]
We can write it as
Required area = 2 [area of ODAO + area of ADCA]