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Simplify

(i) (a2 – b2)2
(ii) (2n + 5)2 – (2n – 5)2
(iii) (7m – 8n)2 + (7m + 8n)2
(iv) (m2 – n2m)2 + 2m3n2

1 Answer

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Best answer

(i) (a2 – b2)2

= (a2)2 – 2(a2) (b2) + (b2)2 (Using identity II)

= a4 – 2a2b2 + b4

(ii) (2n + 5)2 – (2n – 5)2

= {(2n)2 + 2 (2n) (5) + (5)2} – {(2n)2 – 2(2n) (5) + (5)2}
(Using identity I and II)

= (4n2 + 20n + 25) – (4n2 – 20n + 25)

= 4n2 + 20n + 25 – 4n2 + 20n – 25

= 4n2 – 4n2 + 20n + 20n + 25 – 25

= 0 + 40n + 0

= 40n

Alternative Method-

(2n + 5)2 – (2n – 5)2

= {(2n + 5) + (2n – 5)} {(2n + 5) – (2n – 5)}
(Using identity II)

= (4n) (10)

= 40n

(iii) (7m – 8n)2 + (7m + 8n)2

= {(7m)2 – 2(7m) (8n) + (8n)2} + {(7m)2 + 2(7m) (8n) + (8n)2} (Using identity I and II)

= (49m2 – 112mn + 64n2) + (49m2 + 112mn + 64n2)

= 49m2 – 112mn + 64n2 + 49m2 + 112 mn + 64 n2

= 49m2 + 49m2 – 112mn + 112mn + 64m2 + 64n2

= 98m2 + 128n2

(iv) (m2 – n2m)2 + 2m3n2

= [(m2)2 – 2(m2) (n2m) + (n2m)2] + 2m3n2 (Using identity II)

= m4 – 2m3n2 + n4m2 + 2m3n2

= m4 – 2m3n2 + 2m3n2 + n4m2

= m + n4m2

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