+2 votes
in Chemistry by (2.8k points)
closed by

Correct order of oxidizing strength is:-

1 Answer

+3 votes
by (65.3k points)
selected by
Best answer

Correct Answer is option (4) i.e  MnO4 - > Cr2O7 2- > VO2 +

We are given an oxocation (VO2 +) and two oxoanions (Cr2O7 2- and MnO4 -) of the transition metals. The ions in which the central metal atom is present in the highest oxidation state will have the highest oxidising power. In VO2 +, vanadium is present in the +5 oxidation state, while in Cr2O7 2- ion, Cr is present in the +6 oxidation state. Similarly in the MnO4 -, Mn is present in the +7 oxidation state. Thus as the oxidation state of the central metal atom increases in the order

 V < Cr < Mn

therefore the oxidising power of the oxo ions increases in the order

MnO4 - > Cr2O7 2- > VO2 +

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.