Question

Distribute 45 in this way that one part is 7 less than three times of another part.

Answer 1

Let one part be x.

Then according to question second part = 45 – x.

Then, according to question x = 3(45 – x) – 7

⇒ x = 135 – 3x – 7

⇒ x = – 3x + 135 – 7

⇒ x = – 3x + 128

⇒ x + 3x = 128

⇒ 4x = 128

⇒ x = 128/4

⇒ x = 32

Hence, one part = 32

Hence, second part = 45 – 32 = 13

Hence, the required part are 32 and 13.