Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Linear Equations with One Variable by (48.4k points)
closed by

Find three consecutive multiples of 11, whose sum is 363.

1 Answer

+1 vote
by (49.3k points)
selected by
 
Best answer

Let three consecutive multiples of 11 be 11 x, 11(x + 1) and 11(x + 2)

According to question,

11 x + 11(x + 1) + 11(x + 2) = 363

⇒ 11 x + 11 x + 11 + 11 x + 22 = 363

33 x = 363 – 33

⇒ 33 x = 330

⇒ x = 330/33

⇒ x = 10

Three consecutive multiple numbers

11x = 11 x 10 = 110

11(x + 1) = 11(10 + 1) = 11 × 11 = 121

11(x + 2) = 11(10 + 2) = 11 × 12 = 132

Three consecutive multiple numbers are 110, 121 and 132.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...