Let three consecutive multiples of 11 be 11 x, 11(x + 1) and 11(x + 2)
According to question,
11 x + 11(x + 1) + 11(x + 2) = 363
⇒ 11 x + 11 x + 11 + 11 x + 22 = 363
33 x = 363 – 33
⇒ 33 x = 330
⇒ x = 330/33
⇒ x = 10
Three consecutive multiple numbers
11x = 11 x 10 = 110
11(x + 1) = 11(10 + 1) = 11 × 11 = 121
11(x + 2) = 11(10 + 2) = 11 × 12 = 132
Three consecutive multiple numbers are 110, 121 and 132.