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A farmer has enough food for 20 animals for 6 days. If he increases 10 more animals then for how many days this food will be enough?

1 Answer

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Best answer

Let required days be x.

Here inverse relation occurred.

30 : 20 :: 6 : x

Product of outer terms = Product of middle terms

⇒ 30 × x = 20 × 6

⇒ x = (20 x 6)/30 = 4

Hence, the required days are 4.

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