Consider each side of base a and h as the height
So we get c2 = (a2 + 4ah)
It can be written as
h = (c2 – a2)/4a
Here volume can be written as
V = a2 × h
By substituting the value of h
V = (c2a – a3)/ 4
By differentiating w.r.t a
Which is lesser than 0
Hence, V is maximum when a2 = c2/3 and h = c/2√3