Question

Find the slope of the tangent to the curve

(i) y = (x³ – x) at x = 2

(ii) y = (2x² + 3 sin x) at x = 0

(iii) y = (sin 2x + cot x + 2)² at x = π/2

Answer 1

(i) y = (x³ – x) at x = 2

Consider y = (x³ – x) as the equation of curve

By differentiating both sides w.r.t x

(ii) y = (2x² + 3 sin x) at x = 0

Consider y = (2x² + 3 sin x) as the equation of curve

By differentiating both sides w.r.t x

(iii) y = (sin 2x + cot x + 2)² at x = π/2

Consider y = (sin 2x + cot x + 2)² as the equation of curve

By differentiating both sides w.r.t x