Question

Find the equation of the tangent and the normal to the given curve at the indicated point: y² = 4ax at (a/m², 2a/m)

Answer 1

Consider y² = 4ax as the equation of curve

By differentiating both sides w.r.t x

By substituting the values we get

It can be written as

m(ym² – 2am) = –m²x + a

By multiplying inside the bracket

ym³ – 2am² = –m²x + a

We get

m²x +ym³ – 2am² – a = 0