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b^2 = 1.

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asked Jun 27, 2020 in Derivatives by Siwani01 (48.6k points)
closed Jun 27, 2020 by Siwani01

Show that the equation of the tangent to the hyperbola x²/a² – y²/b² = 1 at (x₁, y₁) is xx₁/a² – yy₁/b² = 1.

applications of derivatives
class-12

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answered Jun 27, 2020 by Vikram01 (49.9k points)
selected Jun 27, 2020 by Siwani01

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Consider x²/a² + y²/b² = 1 as the equation of curve

By differentiating both sides w.r.t x

We get

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Show that the equation of the tangent to the hyperbola x^2/a^2 – y^2/b^2 = 1 at (x1, y1) is xx1/a^2 – yy1/b^2 = 1.

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