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Using properties of determinants prove that: |(a2 + 2a,2a + 1,1),(2a + 1,a + 2,1),(3,3,1)| = (1 - a)3

1 Answer

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Best answer

We know that

Taking out (a - 1) common from R1 and R2

On further calculation

Δ = (a – 1)2 {1(2 – a – 1)}

We get

Δ = (a – 1)2 (- a + 1)

Δ = (1 – a)3

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