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in Determinants by (49.9k points)
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Using properties of determinants prove that: |(a + b + c,-c,-b),(-c,a + b + c,-a),(-b,-a,a + b + c)| = 2(a + b)(b + c)(c + a)

1 Answer

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Best answer

Considering LHS

We get

= (a + b) (b + c) (a +c) (1 + 1)

= 2(a + b) (b + c) (c + a)

= RHS

Hence, it is proved.

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