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in Determinants by (49.9k points)
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Using properties of determinants prove that: |(a2,b2,c2),((a + 1)2,(b + 1)2,(c + 1)2,((a - 1)2,(b - 1)2,(c - 1)2)| = -4(a - b)(b - c)(c - a)

1 Answer

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by (48.6k points)
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Best answer

We know that

Taking 2 as common

On further calculation

Δ = 4(a – b) (b – c) (a + b – b – c)

So we get

Δ = 4(a – b) (b – c) (a – c)

It can be written as

Δ = – 4(a – b) (b – c) (c – a)

Hence, it is proved.

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