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in Determinants by (49.9k points)
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Find the area of the triangle whose vertices are A (3, 8), B (-4, 2) and C (5, -1).

1 Answer

+1 vote
by (48.6k points)
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Best answer

A(3, 8), B(-4, 2) and C(5, -1)

On further calculation

= 1/2 (63 + 12)

So we get

= 1/2 (75)

= 37.5 sq. units

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