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in Determinants by (49.9k points)
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Find the area of the triangle whose vertices are  A(-8, -2), B(-4, -6) and C(-1, 5).

1 Answer

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Best answer

A(-8, -2), B(-4, -6) and C(-1, 5)

On further calculation

= 1/2 (28 + 28)

So we get

= 1/2 (56)

= 28 sq. units

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