Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
507 views
in JEE by (65 points)

A projectile is thrown with speed v0 at an angle θ above horizontal from top of a tower of height h. The speed of projectile when it makes an angle β with vertical is

Options:

image

image

image

Should have chosen

image

Please log in or register to answer this question.

1 Answer

0 votes
by (25 points)
  • A body is projected with a velocity v0 at an angle θ then its horizontal velocity becomes v0 cos θ and vertical velocity becomes v0 sin θ
  • At certain point, it is given that the velocity makes angle β with vertical   

                 let the velocity at that point be 'v' then the horizontal velocity becomes vsinβ

                            vertical velocity becomes vcosβ

            In a projectile, horizontal velocity is always constant as the acceleration in that direction is 0

                so,    v0 cos θ = vsinβ 

                              v = v0 cos θ/sinβ 

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...