Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
514 views
in Integers by (49.3k points)
closed by

The rate of decreasing the temperature in a refrigerator is 3°C per minute. A thing whose temperature is 25°C, is kept in refrigerator. After how much time, the temperature of thing will be – 2°C?

1 Answer

+1 vote
by (48.4k points)
selected by
 
Best answer

Temperature of thing = 25°C

Rate of decreasing of temperature = -3°C per minute

Total decrease in temperature of thing after decreasing

from 25°C to – 2°C = (- 2) – 25

= -2 – 25

= – 27°C

Time taken to reach upto – 27°C at the rate of 3°C per minute = 27°C x 1/3°C per minute

= 9 minutes.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...