Question

The zeros of the polynomial 6x² - 3 – 7x are
(A) 3/2, 1/3
(B) -3/2, -1/3
(C) 3/2, -1/3
(D) -3/2, 1/3

Answer 1

Answer: (C) 3/2, -1/3

We have,
f(x) = 6x² - 3 – 7x
      = 6x² – 7x - 3
Now, put f(x) = 0
6x² – 7x – 3 = 0
6x² – 9x + 2x – 3 = 0
3x(2x – 3) + 1(2x – 3) = 0
(2x – 3) (3x + 1) = 0
2x – 3 = 0 or 3x + 1 = 0
2x = 3 or 3x = -1
x = 3/2 or x = -1/3
So, the zeros of given polynomial are 3/2 and -1/3.