Question

The zeros of the polynomial x²-2x -8 are
(A) -4, 2
(B) 4, 2
(C) -4, -2
(D) 4, -2

Answer 1

Answer: (D) 4, -2

We have,
f(x) = x²-2x -8
Now, put f(x) = 0
x²-2x -8 = 0
x²- 4x + 2x -8 = 0
x(x - 4) + 2(x - 4) = 0

(x - 4) (x + 2) = 0
x - 4 = 0 or x + 2 = 0
x = 4 or x = -2
So, the zeros of given polynomial are 4 and -2.