Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.6k views
in Quadratic Equations by (50.9k points)
closed by

If the equation x2 + 4x + k = 0 has real and distinct roots, then
(A) k < 4
(B) k > 4
(C) k ≥ 4
(D) k ≤ 4

1 Answer

+1 vote
by (45.3k points)
selected by
 
Best answer

Answer: (A) k < 4

The given equation is x2 + 4x + k = 0

Here, a = 1, b = 4 and c = k

D = b2 – 4ac

= (4)2 – 4 x 1 x k

= 16 – 4k

The given equation will have real and distinct roots, if

D > 0

16 – 4k > 0

16 > 4k

4k < 16

k < 16/4

k < 4

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...