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+1 vote
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in Chemistry by (30.0k points)

The size of isoelectronic species — F – , Ne and Na+ is affected by 

(a) Nuclear charge (Z ) 

(b) Valence principal quantum number (n) 

(c) Electron-electron interaction in the outer orbitals 

(d) None of the factors because their size is the same. 

1 Answer

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Best answer

The size of an isoelectronic species increases with a decrease in the nuclear charge (Z). For example, the order of the increasing nuclear charge of F– , Ne, and Na+ is as follows: F – < Ne < Na+ Z 9 10 11 Therefore, the order of the increasing size of F– , Ne and Na+ is as follows: Na+ < Ne < F–

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